Re: [oc] Again! modulo arithmetic hardware

[John Sheahan <jrsheahan@optushome.com.au>]

On Tue, Mar 12, 2002 at 12:34:30PM -0800, Tantos Andras wrote:
> Hi!
> 
> It seems I'll make quite of a thread on my own... :-)

ok - I'll bite

> 
> There was a bug in the previous posting. Here's a better one:
> 
> > if (Rand(3..0) < 10) then
> >     Output <= Rand;

so there is 10 chances in 16 of getting 0..9

> > end if;
> > if (Rand(3..0) > 9) and (Rand(3..0) < 15) then
> >     if (Rand(4) = 1) then
> >         Output <= Rand(3..0) - 5;

and also (6 / 16) /2   of getting  (10-15) - 5 or 5 ..10

> >     else
> >         Output <= Rand(3..0) - 10;

and also 6/16 /2 chances of getting (10..15)  -10 or 0--5

the probability of getting 10 is different to all the others.

sorry - not flat enough for a cigar
john


> >     end if;
> > end if;
> > if (Rand(3..0) = 15) then
> >     Output <= Cnt;
>       if (Cnt < 9) then
> >         Cnt <= Cnt + 1;
>       else
>           Cnt <= 0;
>       end if;
> > end if;
> 
> Andras Tantos
> 
> 
> 
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